How to Express a Vector in Terms of Basis Vectors?

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To express the vector y = (3, 1, 2, 5) in terms of the basis vectors e1, e2, e3, and e4, the correct representation is y = 3e1 + 1e2 + 2e3 + 5e4. Each coefficient corresponds to the contribution of the respective basis vector to the overall vector. The discussion clarifies that the values for e1, e2, e3, and e4 are standard basis vectors in a four-dimensional space. There was a point of confusion regarding the coefficient of 0.5, which was corrected to 1 for e2. The final expression accurately reflects the linear combination of the basis vectors.
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Homework Statement



Given the basis vector:

e1 = 1 0 0 0
e2 = 0 1 0 0
e3 = 0 0 1 0
e4 = 0 0 0 1

Express the following vector in terms of the basis:

y = 3 1 2 5

Homework Equations



e1 = 1 0 0 0
e2 = 0 1 0 0
e3 = 0 0 1 0
e4 = 0 0 0 1

y = 3 1 2 5

The Attempt at a Solution



= 3(e1) + 0.5(e2) + 2(e3) + 5(e4)
 
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939 said:

Homework Statement



Given the basis vector:

e1 = 1 0 0 0
e2 = 0 1 0 0
e3 = 0 0 1 0
e4 = 0 0 0 1

Express the following vector in terms of the basis:

y = 3 1 2 5

Homework Equations



e1 = 1 0 0 0
e2 = 0 1 0 0
e3 = 0 0 1 0
e4 = 0 0 0 1

y = 3 1 2 5

The Attempt at a Solution



= 3(e1) + 0.5(e2) + 2(e3) + 5(e4)

Why the .5?
 
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Yeah, what he said ^^
 
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(3, 1, 2, 5)= (3, 0, 0, 0)+ (0, 1, 0, 0)+ (0, 0, 2, 0)+ (0, 0, 0, 5)
= 3(1, 0, 0, 0)+ 1(0, 1, 0, 0)+ 2(0, 0, 1, 0)+ 5(0, 0, 0, 1)
= 3e1+ 1e2+ 2e3+ 5e4
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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