How to Find Area of a Rotated Surface?

[stunner5000pt]

Homework Statement

Find the exact value when y = \frac{x^3}{2} + \frac{1}{6x} in domain \frac{1}{2} \leq x \leq 1 is rotated around the X axis

Homework Equations

Area is given by
A = \int \pi \left(f(x)\right)^2

The Attempt at a Solution

If the above formula is correct, then I should be integrating the following

A = \int_{\frac{1}{2}}^{1} ( \frac{x^3}{2} + \frac{1}{6x})^2 dx

Is this set up alone correct?

 

[CompuChip]

I think the formula you are using is for the volume of the solid of rotation: you can cut it up into thin slices of surface area \pi r^2 = \pi f(x)^2 and "thickness" dx.

Do you have a formula with a 2\pi and an f'? :)

 

[stunner5000pt]

I think the formula you are using is for the volume of the solid of rotation: you can cut it up into thin slices of surface area \pi r^2 = \pi f(x)^2 and "thickness" dx.

Do you have a formula with a 2\pi and an f'? :)

Hmm i think I am mistaken...
I was trying to look this up and foudn the following formula:

A = \int_{a}^{b} 2 \pi f(x) \sqrt{1 + (f'(x))^2} dx

is this the fomula I need to be using?

 

[Dick]

Hmm i think I am mistaken...
I was trying to look this up and foudn the following formula:

A = \int_{a}^{b} 2 \pi f(x) \sqrt{1 + (f'(x))^2} dx

is this the fomula I need to be using?

If it's surface area you want, then that looks right.

 

[stunner5000pt]

If it's surface area you want, then that looks right.

Ok that's perfect...

Now just to clarify, the integral becomes:

2\pi \int_{\frac{1}{2}}^{1} \left( \frac{3x^4+1}{6x^2} \right) \sqrt{1+\left(\frac{9x^4-1}{6x^2}\right)^2} dx


So I was a bit lazy so I plugged into wolfram alpha and got the answer 445\pi/768

is this correct? is there anything that I missed to consider?

 

[Dick]

Ok that's perfect...

Now just to clarify, the integral becomes:

2\pi \int_{\frac{1}{2}}^{1} \left( \frac{3x^4+1}{6x^2} \right) \sqrt{1+\left(\frac{9x^4-1}{6x^2}\right)^2} dxSo I was a bit lazy so I plugged into wolfram alpha and got the answer 445\pi/768

is this correct? is there anything that I missed to consider?

Conceptually you aren't missing anything. In detail, it might be wrong. [Edit: my mistake, it is correct].

 

[stunner5000pt]

Conceptually you aren't missing anything. In detail, it might be wrong. [Edit: my mistake, it is correct].

Thank you :)
Been stressing about these questions for quite some time now