How to Find Final Temperature in a Calorimetry Copper Pot Problem?

AI Thread Summary
To find the final temperature in the calorimetry problem involving a copper pot, water, and an iron block, the heat transfer equation is set up as Qwater + Qiron + Qcopper = 0. The equation for heat transfer is Q = mc(Delta T), where Delta T is the difference between final and initial temperatures. The correct approach involves calculating the heat gained or lost by each component using their respective masses and specific heat capacities. By applying the distributive property and factoring out Tfinal, the final temperature can be isolated and solved. This method ensures accurate results without heat loss.
ziddy83
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Hey what's up,
I am stuck on the following problem.

a copper pot with mass of 0.5kg contains 0.170kg of water at a temperature of 20C. A 0.250kg block of iron at 85C is dropped into the pot. Find the final temperature assuming not heat loss.

Ok, so Here is what i was thinking about doing:

Qwater + Qiron + Qcopper = 0

i know the initial temperature of the system, 20C. i also know the temp of the Iron block. so...How do i find the final T? Q = mc(Delta T), the delta T part is where I am confused. How do i set up the equation so i can solve for Tfinal? Thanks for any help.
 
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Your equation is set up correctly.

\Delta T = T_{final} - T_{initial}

Just use the idea of

m_{copper}c_{copper}(T_{final} - T_{initial copper}) + m_{water}c_{water}(T_{final} - T_{initial water}) + m_{iron}c_{iron}(T_{final} - T_{initial iron}) = 0

Use Distributive of product with respect to addition property, then factor the T final.
 
Sweet...thanks a lot man.
 
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