How to find mu without the force of friction

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SUMMARY

The discussion focuses on calculating the coefficient of friction (mu) for a 2.25 kg block accelerating at 5 m/s² on a 40-degree ramp without knowing the force of friction. The key equations involved include Fw = m*g, Fnet = m*a, and Ff = mu*Fn. The solution involves determining the net force acting on the block and using it to find the frictional force, which is then used to calculate mu. The approach emphasizes the relationship between net force, gravitational force, and frictional force in the context of inclined planes.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Basic knowledge of trigonometric functions (sine and cosine)
  • Familiarity with forces acting on inclined planes
  • Concept of friction and its coefficient (mu)
NEXT STEPS
  • Study the derivation of forces on inclined planes using free-body diagrams
  • Learn about calculating frictional forces in different scenarios
  • Explore advanced topics in dynamics, such as kinetic vs. static friction
  • Investigate the effects of angle and mass on acceleration on ramps
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for practical examples of friction and inclined planes.

Chrismacs
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Homework Statement


Well I am trying to figure out how to find mu if you don't know the force of friction

Homework Equations


An example is a 2.25 kg block is accelerating at an acceleration of 5 m/s/s and is on a 40 degree
ramp. What is the force of friction and what is mu?

The Attempt at a Solution


When I first look at this problem I write what I know

a=5 m/s/s
m=2.25kg
theta=40

and the equations I know:
Fw=m*g
Fnetx(perp)=sin(theta)*w
Fnety(perp)=cos(theta)*w
Ff=mu*Fn
Fn=Fwperp

But you see I think I am doing this problem wrong here because wouldn't the force of the weight parallel be greater than the force of friction?

Please if you can answer ant of my questions will you please do so.

Thank you!
 
Last edited:
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well, I would first find the resultant force, the force that's pulling the object down parallel the ramp.
Force resultant=sin(theta) mass x g

So if there was no friction, then the object would only have that force and would accelerate down more quickly than if there was
friction.

But since there's friction force acting in the opposite direction, then the object doesn't accelerate as quickly. So since Net force is what is currently acting on the object now, I would use
Net Force= Mass x Acceleration,
Net Force= 2.25 x 5

I would find the net force acting on the block. I would then subtract the resultant force from the Net force, and that would equal friction force.

With friction force, I would just then plug it into the equation. F(fric.)= Mu x (mg cos theta)

Note: This may not be correct, since I am also a newbie. However, I'm pretty sure it's right.
 
Last edited:

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