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1. Child on a Swing
This child involves a child swinging on a swing supported by ropes of length 2.5 m. The child's velocity at the bottom of his arc is given as .7 m/s. The goal of the problem is to find the angle between the ropes and the vertical when the child is at his maximum height.
1/2mVi^2 = mgh
divide through by m ---> 1/2Vi^2 = gh
In solving this problem, I was able to find the child's maximum height using the above equation. This I found to be .025 m, however, beyond this point I am at a loss for what to do.
Any help would be greatly appreciated!
This child involves a child swinging on a swing supported by ropes of length 2.5 m. The child's velocity at the bottom of his arc is given as .7 m/s. The goal of the problem is to find the angle between the ropes and the vertical when the child is at his maximum height.
Homework Equations
1/2mVi^2 = mgh
divide through by m ---> 1/2Vi^2 = gh
The Attempt at a Solution
In solving this problem, I was able to find the child's maximum height using the above equation. This I found to be .025 m, however, beyond this point I am at a loss for what to do.
Any help would be greatly appreciated!
