- #1
Sneakatone
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a strong steady wind provides a force of 170 N in a direction 30 degrees east of north on a person. If the person walks first 110 m north and then 190 m east what is the total work done by the wind?
I used W=FDcosθ
170(110)cos(30)=16194.67J
170(190)cos(30)=27972.62
should 110 m north be 90 degrees?
I used W=FDcosθ
170(110)cos(30)=16194.67J
170(190)cos(30)=27972.62
should 110 m north be 90 degrees?