How to get the place of max bending moment ?

AI Thread Summary
The maximum bending moment (BM) in a cantilever beam occurs at the fixed support, despite the presence of reaction forces. This is because a cantilever has only one support, which generates a moment to prevent toppling. The principle of maximum BM at zero shear applies primarily to simply supported beams, where the shear force crosses the horizontal axis. For cantilevers, it is essential to understand the differences in shear and moment behavior compared to simply supported spans. Drawing shear force and bending moment diagrams is recommended for better comprehension of these concepts.
hadeel
Messages
5
Reaction score
0
what i know is the the max BM at zero shear
but it is said that max BM in the cantileaver beam is at the fixation
how?
is the shear there )0) ??
there is reastion so how?
 
Engineering news on Phys.org
Yes the max bending moment in a cantilver occurs at the root or fixed support.

A cantilever has only one support so there must be a moment at that support to stop it toppling over.

what i know is the the max BM at zero shear

Check again with your notes or textbook.
This only applies to simply supported spans. These must have two supports and there is a maximum in the BM curve at the same point as the vertical shear curve crosses the horizontal axis.


Have you tried drawing some BM and SF diagrams?
You should do this for both cantilevers and simply supported beams.

Try also beam with an overhang at one or both ends
 
Studiot said:
This only applies to simply supported spans.

Not quite. It only applies where the shear force is a continuous function, for example a distributed load along the beam. It doesn't apply at points on the beam where the shear load is discontinuous.
 
thanks a lot

but please when the max BM at zero shear is applied
 
thanks a lot

but please when the max BM at zero shear is applied

It is not clear whom you were thanking for what.

I suggested you draw some diagrams.

Did you do this?

I have attached a very simple comparison of a simply supported beam with a cantilever.

Do you understand the diagrams I have drawn and how to obtain them?
 

Attachments

  • beams5.jpg
    beams5.jpg
    10.5 KB · Views: 508
Hi all, I have a question. So from the derivation of the Isentropic process relationship PV^gamma = constant, there is a step dW = PdV, which can only be said for quasi-equilibrium (or reversible) processes. As such I believe PV^gamma = constant (and the family of equations) should not be applicable to just adiabatic processes? Ie, it should be applicable only for adiabatic + reversible = isentropic processes? However, I've seen couple of online notes/books, and...
I have an engine that uses a dry sump oiling system. The oil collection pan has three AN fittings to use for scavenging. Two of the fittings are approximately on the same level, the third is about 1/2 to 3/4 inch higher than the other two. The system ran for years with no problem using a three stage pump (one pressure and two scavenge stages). The two scavenge stages were connected at times to any two of the three AN fittings on the tank. Recently I tried an upgrade to a four stage pump...
Back
Top