How to measure the length of metal sheet coil?

AI Thread Summary
To measure the length of a metal sheet coil, two formulas are commonly referenced: L = 0.065449 (OD^2 - ID^2) / T and L = ((ID + OD)/2 X 3.14 * # of wraps on the coil )/12. The first formula incorporates a constant that converts inches to feet, while the second averages the inner and outer diameters. A more accurate approach suggested involves using integration to derive the length from the area of the coil, leading to the formula Length = π/4 * (OD^2 - ID^2) / T. Additionally, it's important to consider the thickness of any insulation if the coil is part of an inductor.
qnikchen
Messages
2
Reaction score
0
Hi everyone,

I have been trying to find an equation to measure the length of a coil. The coil is a metal sheet that wraps around the loops as it creates. It looks like a roll of tape. I have been using two different formula, but it is not giving me the right results.

1. L = 0.065449 (OD^2 - ID^2) / T; where OD is the outer diameter, ID the inner diameter, and T the thickness of the sheet.

2. L = ((ID + OD)/2 X 3.14 * # of wraps on the coil )/12.

I am not sure if I am using the right formula, but can some please give me a hint on this?

Thank you
 
Engineering news on Phys.org
Where did you get those equations? Did you derive them?
 
Hi Dr. D.

Those are found online. Both formulas takes the number in inches, and convert them in feet.
 
To get a better result andto gain more understanding, try working the problem from first principles using integration.
 
qnikchen said:
... where OD is the outer diameter, ID the inner diameter, and T the thickness of the sheet.

The area of metal at the end of the roll is; Area = (π * (OD/2)2) – (π * (ID/2)2)
Therefore, Area = π/4 * ( OD2 – ID2 )

The length of the coil will be Area / T
Therefore, Length = π/4 * ( OD2 – ID2 ) / T

The 0.065449 in your first equation is π/4, divided by twelve to convert from inches to feet.
 
qnikchen said:
Hi everyone,

I have been trying to find an equation to measure the length of a coil. The coil is a metal sheet that wraps around the loops as it creates. It looks like a roll of tape. I have been using two different formula, but it is not giving me the right results.

1. L = 0.065449 (OD^2 - ID^2) / T; where OD is the outer diameter, ID the inner diameter, and T the thickness of the sheet.

2. L = ((ID + OD)/2 X 3.14 * # of wraps on the coil )/12.

I am not sure if I am using the right formula, but can some please give me a hint on this?

Thank you
L=[square root (OD^2 - ID^2)] x PI x turns

turns= (OR-IR)/foil thickness
Remember that most foil coils do have a foil of insolation parallell with the copper foil (If it is intended to be an inductor. So foil thickness should be both combined.

Vidar
 
I have Mass A being pulled vertically. I have Mass B on an incline that is pulling Mass A. There is a 2:1 pulley between them. The math I'm using is: FA = MA / 2 = ? t-force MB * SIN(of the incline degree) = ? If MB is greater then FA, it pulls FA up as MB moves down the incline. BUT... If I reverse the 2:1 pulley. Then the math changes to... FA = MA * 2 = ? t-force MB * SIN(of the incline degree) = ? If FA is greater then MB, it pulls MB up the incline as FA moves down. It's confusing...
Back
Top