How to parameterize these surfaces?

Sho Kano
Messages
372
Reaction score
3

Homework Statement


Calculate ##\iint { y+{ z }^{ 2 }ds } ## where the surface is the upper part of a hemisphere with radius a centered at the origin with ##x\ge 0##

Homework Equations


Parameterizations:
##\sigma =\left< asin\phi cos\theta ,asin\phi sin\theta ,acos\phi \right> ,0\le \phi \le \frac { \pi }{ 2 } ,\frac { -\pi }{ 2 } \le \theta \le \frac { \pi }{ 2 } \\ N=(asin\phi )\sigma \\ \left| N \right| ={ a }^{ 2 }sin\phi \\ \\ \alpha =\left< rcos\theta ,rsin\theta ,0 \right> ,0\le r\le a,\frac { -\pi }{ 2 } \le \theta \le \frac { \pi }{ 2 } \\ N=-k\\ \left| N \right| =1##

The Attempt at a Solution


are these the right parameterizations?
 
Physics news on Phys.org
Check for yourself: ##\ \sigma =\left< a\sin\phi \cos\theta ,a\sin\phi \sin\theta ,a\cos\phi \right> \ ##seems right to me. For ##\ \iint ds\ ## you would then get ##\ \pi a^2, \ ## right ?

It is not clear to me what you do to express ##\ ds \ ##. What is ##N## and what is the function of ##N## ?
 
BvU said:
Check for yourself: ##\ \sigma =\left< a\sin\phi \cos\theta ,a\sin\phi \sin\theta ,a\cos\phi \right> \ ##seems right to me. For ##\ \iint ds\ ## you would then get ##\ \pi a^2, \ ## right ?

It is not clear to me what you do to express ##\ ds \ ##. What is ##N## and what is the function of ##N## ?
Oh sorry, by the integral I mean a surface integral. N is the normal. Both parameterizations seem right to me...i originally had ##a## instead of ##r## for the second parameterization. But that would just give me a circle, not a disk (a surface)
 
Are we mixing up two threads with almost the same title ?
Not clear to me why you need ##N## in this thread. But you sure need ##ds## and I haven't seen how you are going to express that in the parameters
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top