How to prove algebraic constructability of a 30 degree angle?

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Homework Statement



I don't know how to approach this proof, does this amount to proving that you can construct a line segment of length sin(30)?

Homework Equations


The Attempt at a Solution

 
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Syrus said:

Homework Statement



I don't know how to approach this proof, does this amount to proving that you can construct a line segment of length sin(30)?


Homework Equations





The Attempt at a Solution


Not sure what this question is asking for exactly, but if it's a matter of just showing you can construct the angle, the most obvious way is to construct an equilateral triangle and bisect the angle. Or construct the perpendicular bisector of one side and produce it to one of the vertices.
 
Let each side of the equilateral be 2 units length. When you bisect the angle, you will get sin (30) = 1/2
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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