How to prove whether a function is differentiable

haha1234
Messages
109
Reaction score
0

Homework Statement



Suppose that f is differentiable at x . Prove that ƒ(x)=lim[h→0] \frac{ƒ(x+h)-ƒ(x-h)}{2h}

Homework Equations





The Attempt at a Solution


I think that it may be proved by first principle,but I cannot rewrite the limit into the form of lim[h→0] \frac{ƒ(x+2h)-ƒ(x)}{2h}
So how can I solve this question?
THANKS
 
Physics news on Phys.org
You probably mean f'(x). You can rewrite it via u = x-h.
 
haha1234 said:

Homework Statement



Suppose that f is differentiable at x . Prove that ƒ(x)=lim[h→0] \frac{ƒ(x+h)-ƒ(x-h)}{2h}

I assume this is f'(x) = ...

Homework Equations





The Attempt at a Solution


I think that it may be proved by first principle,but I cannot rewrite the limit into the form of lim[h→0] \frac{ƒ(x+2h)-ƒ(x)}{2h}
So how can I solve this question?
THANKS

Use f(x+h) - f(x-h) = (f(x+h) - f(x)) + (f(x) - f(x-h))
 
  • Like
Likes 1 person
pasmith said:
I assume this is f'(x) = ...



Use f(x+h) - f(x-h) = (f(x+h) - f(x)) + (f(x) - f(x-h))

Sorry,but it maybe equals to 0.:confused:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top