How to Solve Log Equations with a Variable Base

  • Thread starter Thread starter ilygurlie
  • Start date Start date
  • Tags Tags
    Base Log
AI Thread Summary
To solve the log equation log base x of 216 equals 6, it can be rewritten in exponential form as x^6 = 216. The next step involves taking the sixth root of both sides, which simplifies to x = 216^(1/6). While some participants suggested using a calculator for a decimal approximation, others emphasized the importance of finding an exact value through simplification, noting that 216 can be factored as 2^3 * 3^3. Ultimately, the discussion highlights the confusion around whether an exact answer is required or if a decimal approximation suffices.
ilygurlie
Messages
3
Reaction score
0

Homework Statement


Log [with base x]216 =6
Find x


Homework Equations





The Attempt at a Solution



Ok, so I put the log equation into exponential form.
It now becomes:
x^6=216
I'm lost on what to do next.. I've tried taking the e and ln of both sides, but when I check it, it's not right. Do I just plug it into my calc? I thought there was some way to do this algebracally... please help!
 
Physics news on Phys.org


To the best of my knowledge, this is as simplified as it can be unless you want a decimal answer, in which case you'd just take the sixth root of 216 on your calculator.

What were you actually asked to do? Just find X? Or something else?

There is no reason to use e or ln in this equation. Those are only used in equations that start off with either e or a natural log (typically when working with continually compounded interest) - you don't just bring them in arbitrarily.
 


Take both sides of x^6=216 to the power of (1/6).
 


Yeah, I'm really confused... My teacher wants an exact, decimal answer so I guess I'll just do it with my calc... but I really thought that was some way without it..
 


It's (216)^(1/6). You can simplify that if you factor 216=2^3*3^3.
 


An "exact decimal answer"? There is none!
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top