How to Solve Vertical Spring and Pulley Homework Problems?

AI Thread Summary
To solve the first homework problem, apply Hooke's Law, where the spring constant K can be calculated by multiplying the weight of the 4 kg load (39.2 N) by the stretch in meters (0.1 m), resulting in K = 392 N/m. For the second problem, use Newton's second law to set up equations for each mass, noting that all masses share the same acceleration and that the system moves clockwise. The tensions in the strings can be represented as T12 and T23, leading to three equations for the unknowns: T12, T23, and acceleration (a). To find the tension, the formula T = (m1 * m2 * m3 / (m1 + m2 + m3)) * g can be used, and acceleration can be determined from the established equations. Understanding these concepts will help in solving both problems effectively.
Vxismyname
Messages
3
Reaction score
0
I have two homework problems i need help with one is:
1) A 4kg load is hanging on the bottom of a vertically positioned spring that stretches 10 cm down. Find K of the sping.

2) There are three blocks connected by a string. m1 is 10 kg, m2 is 20kg.
m1, and m2 are connected at the top of a surface and m3=1kg, is hanging of the end of a pulley. looks kinda like this:

[ m1 ]----[ m2 ]-----O
xxxxxxxxxxxxxxxxxxxxx|
xxxxxxxxxxxxxxxxxxxxx|
xxxxxxxxxxxxxxxxxxx [m3]

a) find the acceleration of the system.
b) the tension in the two strings
 
Physics news on Phys.org
Vxismyname said:
I have two homework problems i need help with one is:
1) A 4kg load is hanging on the bottom of a vertically positioned spring that stretches 10 cm down. Find K of the sping.

2) There are three blocks connected by a string. m1 is 10 kg, m2 is 20kg.
m1, and m2 are connected at the top of a surface and m3=1kg, is hanging of the end of a pulley. looks kinda like this:

[ m1 ]----[ m2 ]-----O
xxxxxxxxxxxxxxxxxxxxx|
xxxxxxxxxxxxxxxxxxxxx|
xxxxxxxxxxxxxxxxxxx [m3]

a) find the acceleration of the system.
b) the tension in the two strings

The first of these is a direct application of Hooke's Law. The restoring force of a spring is proportional to the amount it is stretched.

For your second problem, call the tensions in the strings T12, and T23. Use Newton's second law to write an F = ma equation for each of the three masses in the problem. This will give you three equations. Note that all the masses must have the same magnitude of acceleration, and that the motion will be in a clockwise sense. You will have three equations for three unknowns: T12, T23 and a. See if you can set up and solve those three equations.
 
im sorry i must be a complete idiot but i really cannot figure this out. I find that F= -kx. So For the first one do i multiply the 4kg weight by 9.8 to get Newtons and then divide by 10cm but convert that to meters so .1 meters. So 4kg (9.8) = 39.2 / .1 = 392 N/m is -k?
 
Yes that's correct but use -9.8 for gravity so k becomes a positive number that way -k is actually a negative value. Understand?
 
ok i think i got that last one thank you, as for my other problem i haven't a clue to figure it. For Tension do i just put T= (m1m2m3/m1+m2+m3)g? and what do i do to find acceleration?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top