How to support a sign on our museum wall?

AI Thread Summary
To support a 12-foot triangular sign weighing 200 pounds on a museum wall, two guy wires anchored 12 feet apart at a 45-degree angle are recommended. Each wire will bear approximately 150 pounds of load, so selecting stainless steel cable with a diameter of at least 4mm (or 3/16") is advisable for safety. It's important to consider the yield strength of the cable and potential adverse weather conditions, which may require stronger materials. Overestimating cable strength is prudent to ensure reliability and safety. Using a thicker cable can prevent failures at anchor points or welds before the cable itself gives way.
agap015
Messages
2
Reaction score
0
Hi all,

I went to an engineering school 40 years ago but never finished, so I kind of know that this is easily solveable.

I have a triangular sign 12' long (attached to wall) that is 2 1/2' thick and sticks out from the wall 6'. If I use 2 guy wires anchored to the wall 12' apart, that meet the sign at a 45* angle at the point, how large should the wires (stainless steel cable) be in diameter?

The sign weighs 200# total.

The sign is to be attached to our local museum announcing an event.



*
* *
*
* *
*
* *
*
* *
*
* *
*
* *
*******************************
* *
* *
*******************************


Thanks

George
 
Physics news on Phys.org
I'm a physicist, but pretty far removed from engineering, so take it for what it's worth. Hopefully, somebody better qualified will come along.

If I understand your setup correctly, each wire is under roughly 150lb of load. (A diagram would help to make sure.) You want this to be within yield strength for the wire, to give yourself a bit of an overhead. Of course, there are steel cables, and then there are steel cables. But you should be able to count on at least 200MPa. That means wire just a touch over 2mm in diameter. So you should go with at least 11 gauge (AWG) for this.

Keeping the load within yield strength should make the structure reliable enough, and if things go wrong, should be able to take nearly twice as much load for a short while. But if you expect adverse weather, such as winds or snows, you'd have to account for that separately.
 
Thanks for the reply.

2MM isn't very large. I will probably use 3/16" cable or about 4MM. The sign is a half scale theater marque. It will showcase our town theater.

Thanks

George
 
I am also an owner of a Museum.

I agree with K^2 that it is simply prudent to "overestimate" on the side of safety in supporting this marque. What's the difference in cost or difficulty of using a "stronger than you think is mimimally necessary cable"?

Bobbywhy
 
4mm really ought to do it. I'd expect anchor points or welds on the marquee to go before a 4mm cable does.
 
Thread 'Question about pressure of a liquid'
I am looking at pressure in liquids and I am testing my idea. The vertical tube is 100m, the contraption is filled with water. The vertical tube is very thin(maybe 1mm^2 cross section). The area of the base is ~100m^2. Will he top half be launched in the air if suddenly it cracked?- assuming its light enough. I want to test my idea that if I had a thin long ruber tube that I lifted up, then the pressure at "red lines" will be high and that the $force = pressure * area$ would be massive...
I feel it should be solvable we just need to find a perfect pattern, and there will be a general pattern since the forces acting are based on a single function, so..... you can't actually say it is unsolvable right? Cause imaging 3 bodies actually existed somwhere in this universe then nature isn't gonna wait till we predict it! And yea I have checked in many places that tiny changes cause large changes so it becomes chaos........ but still I just can't accept that it is impossible to solve...
Back
Top