How to tell if an object is moving or not?

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To determine if an object on an incline is moving, one must rely on calculations rather than visual observation. Given the masses, the coefficient of friction, and the incline angle, static friction calculations can reveal whether the system will start moving. Specifically, the force due to gravity acting on the block must be compared to the maximum static friction force. If the gravitational force exceeds the static friction force, the block will move; otherwise, it remains stationary. Accurate calculations are essential to decide between using static or kinetic friction in this scenario.
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Say that there's a ramp with a block on it, with a string attached to the block and to a massless, frictionless pulley at the top of the ramp, and the pulley connecting the string to another block. What if both of the masses are really close and there is friction on the incline but you can't tell if it's moving or not. What would you do to tell if it's moving or not?
 

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Watch it for a long time? If you are serious take a precise measurement, wait a while and take another measurement.
 
@mathman

No, I mean by calculations, not by visual. Say you're given the mass of each block, the kinetic/static friction coefficient, and the angle of the incline.

What would you do to calculate if it's moving or not, so you can know whether to use static or kinetic friction?
 
The wording of the question tells you you need to calculate static friction; static friction is what tells you if (starting from a stop), the system will begin to move or not.
 
Cos of angle x M has to be larger than Cf static
 
mtworkowski@o said:
Cos of angle x Mg has to be larger than CfxMg static
 
So I know that electrons are fundamental, there's no 'material' that makes them up, it's like talking about a colour itself rather than a car or a flower. Now protons and neutrons and quarks and whatever other stuff is there fundamentally, I want someone to kind of teach me these, I have a lot of questions that books might not give the answer in the way I understand. Thanks
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