How you put gravity in for the equation

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The discussion centers on the correct application of gravity in kinematic equations, specifically in the formula v = v0 + at. Gravity is defined as ±9.80 m/s², and its sign depends on the chosen coordinate system. When using a coordinate system where the y-axis points upwards, acceleration due to gravity should be represented as ay = -9.80 m/s². Conversely, in a system where downward is positive, gravity is represented as g = +9.80 m/s².

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therealkellys
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I realize this probably sounds like a simple question, but I was just wondering how you put gravity in for the equation. I know that gravity is equal to +/-(9.8 m/s^2). However, when you are putting it in an equation such a v=v0+at...do you use 9.8/(t^2) or just the rate...9.8? Thanks in advance for the help:biggrin:
 
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therealkellys said:
I realize this probably sounds like a simple question, but I was just wondering how you put gravity in for the equation. I know that gravity is equal to +/-(9.8 m/s^2). However, when you are putting it in an equation such a v=v0+at...do you use 9.8/(t^2) or just the rate...9.8? Thanks in advance for the help:biggrin:


You just put in 9.80 m/s^2 where "a" appears in the equation.

Actually, be careful about the sign. There are different conventions in the litterature.

Using a y-axis pointing up, you may encounter [itex]v_y= v_{y0} + a_y t[/itex] in which case [itex]a_y = -9.80 m /s^2[/itex] or you may encounter [itex]v_y= v_{y0} - g t[/itex] in whcih case you use g = +9.80 m/s^2.


Patrick
 
Since acceleration is a vector quantity, it is always -9.8m/s
 

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