Hydraulics and pressure problem

AI Thread Summary
The discussion revolves around a hydraulic system with two pistons, where pressure applied to one piston affects the movement of the other. The problem involves calculating how high the larger piston will rise when a force of 250N is applied to the smaller piston, which is pressed down by 6.0 cm. The key to solving this problem lies in understanding that the volume displaced by the smaller piston must equal the volume displaced by the larger piston. The area of the smaller piston is given as 2.0 cm², and the radius of the larger piston is assumed to be 6 cm. Clarification is needed regarding the dimensions and the relationship between the areas and heights of the pistons to solve the problem accurately.
justduy
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Homework Statement


The hydraulic system is this: It has two stamps (Unsure of how I am to translate that word). Basically it is the plate on which we apply pressure. You apply pressure on one of them, the other goes up. The question is:
How high will the big stamp move upwards when the small one is pressed down with a force F to 6 .0 cm?

Area of the small one = 2.0 cm^2
Radius of the small one = 6 cm

F = 250N

The Attempt at a Solution


The proposed solutions is just answering with this: a (area of the small one) * h (6.0 cm) = AH

ah = AH => H = (ah)/A

I don't understand why?

Thank you in advance.
 
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I think for "stamp", the word you are looking for is "piston".
 
SteamKing said:
I think for "stamp", the word you are looking for is "piston".

Yep, that's it.
 
justduy said:

Homework Statement


The hydraulic system is this: It has two stamps (Unsure of how I am to translate that word). Basically it is the plate on which we apply pressure. You apply pressure on one of them, the other goes up. The question is:
How high will the big stamp move upwards when the small one is pressed down with a force F to 6 .0 cm?

Area of the small one = 2.0 cm^2
Radius of the small one = 6 cm

F = 250N

The Attempt at a Solution


The proposed solutions is just answering with this: a (area of the small one) * h (6.0 cm) = AH

ah = AH => H = (ah)/A

I don't understand why?

Thank you in advance.
Think about volumes. When one piston is pushed down into the fluid, what volume is displaced? How does that relate to what the other piston does?
 
justduy said:
Area of the small one = 2.0 cm^2
Radius of the small one = 6 cm
I assume you meant to say that the radius of the LARGE piston is 6 cm (not the small one).
 
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