Hydraulics, Flow rate from Bernoulli Equation

AI Thread Summary
The discussion focuses on calculating the flow rate of petrol through a Venturi meter using the Bernoulli equation. Given the diameters of the meter and the height difference in the manometer, the pressure difference is calculated to be 1601 Pa. The user attempts to solve the equation but is unsure about their results, particularly the values of 0.093 and 0.058, which are derived from substituting flow rate for velocity in the equation. The expected flow rate is 39.3 l/s, prompting a request for clarification on the calculations. The conversation emphasizes the application of Bernoulli's principle and the importance of accurate unit conversions in fluid dynamics.
warrio1010
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Homework Statement


Flow rate in Venturi meter of Petrol (SG 0.85).

Diam1 - 0.2m Diam2 - 0.15m

Height Diff in manometer of Mercury (SG 13.6) 0.012m, so Δp= 13600 x 9.81 x 0.012 = 1601?

Cd = 0.98

Homework Equations


Bernoulli,
p/ρg + U2/2g + Z

U=Q/A


The Attempt at a Solution



Inserting and equating the values into bernoulli i ended up with,

0.192 = Q22/0.093 - Q12/0.058

Not sure if this i right because i can't seem to go anywhere from here.

THE GIVEN ANSWER IS 39.3 l/s

Thanks a lot for any help.
 
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Q1 equals Q2. How are the numbers 0.093 and 0.058 computed?
 
They are calculated from 2g x A after subbing u for Q/A.
 
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