Hydrogen vs. Doubly Ionized Lithium: Which Has More Optical Spectrum Lines?

  • Thread starter Thread starter Jacob87411
  • Start date Start date
  • Tags Tags
    Lines Transition
AI Thread Summary
The discussion centers on the comparison of optical spectrum lines between hydrogen and doubly ionized lithium. It is noted that both species have one electron, leading to speculation about their spectral lines. Participants suggest that doubly ionized lithium may have more optical lines due to its additional complexity despite having the same number of electrons as hydrogen. The conversation highlights the importance of electron transitions in determining the number of spectral lines. Ultimately, the conclusion leans towards lithium having more lines, although uncertainty remains.
Jacob87411
Messages
170
Reaction score
1
Assuming that all transitions are possible, will the optical spectrum (380nm to 700nm) of hydrogen have more or fewer lines than the optical spectrum of doubly ionized lithium?

Im not sure on this one but I think its lithium, but like I said I am not sure
 
Physics news on Phys.org
Why?What is the # of electrons for the 2 species...?

Daniel.
 
The lithium has more so it has more lines?
 
The lithium is doubly ionized,so it has one electron,just like the hydrogen.

Daniel.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Quantum Electron Energy Level for Hydrogenic atom
Replies
3
Views
4K
Spectrum & energy level of neutral hydrogen
Replies
1
Views
2K
I J0524-0336, surprisingly high Li concentration
Replies
2
Views
2K
Which Letter Represents a Star Similar to the Sun Based on Emission Spectra?
Replies
10
Views
2K
Observing M87's spectral of light
Replies
3
Views
2K
A Power spectral density of a laser's frequency noise
Replies
6
Views
2K
Calculating the Hydrogen Spectrum: Understanding Energy Levels and Transitions"
Replies
3
Views
3K
Advice needed for science project.
Replies
2
Views
2K
How Does the Zeeman Effect Alter the Wavelength of Hydrogen's Paschen Lines?
Replies
3
Views
3K
How Does Thermal Energy Compare to Ionization Energy in a Flame?
Replies
5
Views
7K

Hot Threads

Recent Insights

Back
Top