Hydromechanics - Flow from a tank with one outflow

  • Thread starter Thread starter Maag
  • Start date Start date
  • Tags Tags
    Flow Tank
AI Thread Summary
The discussion focuses on deriving a mathematical model for fluid flow from a tank with a single outflow, utilizing Bernoulli's equation under the assumptions of incompressibility and laminar flow. The derived equation connects the fluid's velocity and height, leading to a differential equation that can be solved using separation of variables. The author seeks guidance on which physical phenomena to include in their paper, specifically mentioning gravity and turbulence. Although turbulence is acknowledged as a factor that will occur in practical experiments, the author initially assumes laminar flow to simplify the mathematics. The conversation highlights the balance between theoretical modeling and practical experimentation in fluid dynamics.
Maag
Messages
5
Reaction score
0

Homework Statement


I'm currently working on a project which has to do with flow from a tank with one outflow. I have to set up a mathematical equation which describes the flow. Furthermore I have to explain the physics behind the model.

592Wi.jpg


The image shows the container and the outflow.
In order to describe the flow I have to assume that the fluid is incompressible (that the density is the same throughout the fluid), and that the flow is laminar. Also, the fluid is under the influence of a pressure p, the gravitation g and the fluid has the density ρ, by this Bernoullis equation can be used:

p1 + ρgy1 + 0,5ρv12 = p2 + ρgy2 + 0,5ρv22

(they're supposed to be 1 and 2 on the different sides, not 22 and 12)
Where y is the height and v is the velocity of the fluid. From this the formula for a free falling body in the gravitational field can be derived:

v = √(2gy)

Here v describes the velocity of the fluid exiting the container.

Now that the formula for a free falling body has been derived I will take a closer look at the mathematical formula that I have to derive:

With starting point in the formula derived from Bernoullis equation we can see a connection between v and y, which means an equation with two unknown quantities, therefore I have to create another equation where v and y is included. One assumes that the amount of water dVcontainer leaving the container during the time dt is the same amount dVoutflow which leaves the outflow, this is the sentence of mass conservation. To set up the equation I will use the height of the the fluid in the container as a function of the time t, h(t). The cross section of the outflow A, and the cross section of the container B. Both B and A are constants.

First I will see how far the fluid flows during dt:

s = v*dt

Afterwards the equation derived from bernoulli will be inserted:

dVoutflow = -√(2g*h(t)) * A * dt

The minus is included because the amount of fluid is reduced. Also the amount of water leaving is dependant on the cross section of the outflow. Now the volume of the container can be set up:

dVcontainer = B*dh(t)

It was assumed that the amount of water leaving the container is the amount of water leaving the outflow, therefore:

dVoutflow = dVcontainer

-√(2g*h(t)) * A * dt = B*dh(t) <=> (dh(t))/dt) = -(A/B)*√(2g*h(t))

This differentialequation can then be solved with the method "separation of variables", which then ends up with:

∫(1/√(h(t))) * dh(t) = ∫-(A/B) *√(2g) * dt

Which then is the solution to the differential equation.

My question is then: Which physical phenomenons and forces should I include in my paper when arguing for the physics behind the equation? I'm already including gravitation and turbulence (Turbulence is created due to high speeds and viscosity, viscosity is internal friction, friction = force)

Thanks in advance.

-Maag
 
Physics news on Phys.org
You have already stated in your assumptions that the fluid is incompressible and the flow is laminar. Therefore, the flow is not turbulent by definition.
 
That was an assumption I had to make in order to make it simple. If I would have to bring in turbulence the mathematics would be incredibly difficult, since turbulence is very hard to define and work with. However, I still have to describe it because turbulence WILL occur in my experiment which I will set up later on.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top