Hyperbolic substitition question:

  • Thread starter Thread starter Zeth
  • Start date Start date
  • Tags Tags
    Hyperbolic
Zeth
Messages
23
Reaction score
0

Homework Statement



\int \!\sqrt {1+{v}^{2}}{dv}

Homework Equations



Maple tells me that I have to throw in an arcsinh into the solution some how.

The Attempt at a Solution



I've tried substituting with tan(x) but that got me no where and from the solution I'm given:

1/2\,v\sqrt {1+{v}^{2}}+1/2\,{\it arcsinh} \left( v \right)

I'm not sure how you get the first term and I know that arcsinh(v) is the integral of 1/sqrt(1+v^2)
 
Physics news on Phys.org
If the answer involves inverse sinh, why not put sinh (or cosh or tanh) into the equation?
 
If you don't exactly like arcsinh, just rewrite sinh in terms of the exponential function and find its inverse. This shows you that arcsinh is just a fancier way of writing: \log_e (x + \sqrt{x^2+1})

Edit: P.S. u= tan x was a good idea :) Go along with it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top