What is the magnitude and direction of the second force vector in this scenario?

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The discussion revolves around a physics problem involving two force vectors, F1 and F2, where F1 is 200 N east and the resultant vector is 400 N along the east-west line. The confusion arises regarding the direction of F2, with some suggesting it could be described as having a north component. However, it is clarified that F2 must be 600 N west, as adding 200 N east and 600 N west results in a net force of 400 N west. The participants agree that the answer book's reference to "north" is incorrect, as the vectors only lie along the east-west axis. Ultimately, the correct interpretation is that F2 is simply 600 N west, without any northward component.
LuvIz4ever
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I can't figur this out!

Now i got the answer to this problem but i am so confused at this one thing... how is it that the answer is 200 N of East and 600 N of west


the question is

A force vector F1 points due east with a magnitude of 200 Newtons and a second force F2 is added to F1. The resultant of the two vectors has a magnitude of 400 Newtons and points along the East and west line. Find the magnitude and direction of F2 note that there are 2 answers.


My question is I know the answers 2oo east and 6oo west but why north of east or north of west.
 
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LuvIz4ever said:
how is it that the answer is 200 N of East and 600 N of west
I suspect that the N stands for Newtons, not north.
 
Thanks But...

Actually in the answer book it tells me it is North... I think it is weird though becuase of the fact that it has nothing about North.. in the question
 
The answer in your book must be wrong. You have an initial vector pointing along the east-west line. If you add to it a vector with any component at all in the north-south direction, the resultant cannot possibly be entirely along the east-west line. I suspect the Doc is absolutely right.
 
... I figured that... thanks! sooooo! Much!
 
simply put, there is 200 going "right" and 600 going "left" add 200 + (-600) leads to a net of 400, and this 400 is along EW or as most would say x-axis..

yw
 
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