I dont know if I did the problem right check please.

[yaho8888]

[SOLVED] I don't know if I did the problem right check please.

Homework Statement

A jet is diving vertically downward at 1200km/hr
the pilot can withstand a maximum acceleration of 4G, before losing consciousness, at what height must the plane start a quarter turn to pull out of the dive? Assume the speed constant.

Homework Equations

A=V^2/r

The Attempt at a Solution

for this circular motion we know that h = radius of the circle
so
4G=(1200km/hr)^2/h
4G=4*9.8m/s=39.2m/s=508032km/hr^2(Not sure if convert it right)
508032=1200^2/h
h=2.834Km
Is this right, the answer has to be in Km so I convert the 4G.

 

[Shooting Star]

If you want the ans in km/hr, convert everything to those units.

4g = v^2/h =>
4*(9.8/1000)/(1/3600)^2 = 1200^2/h. The value of h will be in kms.

EDIT: 1/3600 corrected (1/3600)^2, after being pointed out by yaho8888.

 

[PhanthomJay]

Looks good; you incorrectly typed m/s instead of m/s^2 in your 4G calculation, but the math came out OK.

 

[yaho8888]

If you want the ans in km/hr, convert everything to those units.

4g = v^2/h =>
4*(9.8/1000)/(1/3600) = 1200^2/h. The value of h will be in kms.

wouldn't that be 4*(9.8/1000)/(1/3600)^2

 

[Shooting Star]

wouldn't that be 4*(9.8/1000)/(1/3600)^2

Yes. Thanks for pointing out the typo. I'll edit the post.