agirlsrepublic
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a velocity selector consists of magnetic and electric fields. if B= 0.015 find the value of E such that a 750 eV electron is moving along the + x- axis and is undeflected.
this is what i did..
the magnetic force=electric force so qvB=qE or vB=E
K= .5 mv^2 and r= mv/qB so k =[.5r^2q^2B^2]/m and if you simplify you get:
r= [(2km)^.5]/qB
r= {[2*750*1.6*E-19*9.11E-31]^.5}/1.6E-19*.015= 1.38E-16
if v=rqm/m then v = [1.38E-6*1.6E-19*.015]/9.11E-31 = 3.64E3
since E= vB then E= 3.64E3*0.15= 5.45E1
but this is not the answer
the answer is 244 KV/m
someone please help its driving me mad and i have a test soon
thanks!
this is what i did..
the magnetic force=electric force so qvB=qE or vB=E
K= .5 mv^2 and r= mv/qB so k =[.5r^2q^2B^2]/m and if you simplify you get:
r= [(2km)^.5]/qB
r= {[2*750*1.6*E-19*9.11E-31]^.5}/1.6E-19*.015= 1.38E-16
if v=rqm/m then v = [1.38E-6*1.6E-19*.015]/9.11E-31 = 3.64E3
since E= vB then E= 3.64E3*0.15= 5.45E1
but this is not the answer
the answer is 244 KV/m
someone please help its driving me mad and i have a test soon
thanks!