I figuring out the kg of ice can you melt

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Homework Help Overview

The problem involves determining how many kilograms of ice can be melted with a specified amount of heat energy, given as 178,000 calories. The context is centered around the concepts of heat transfer and phase changes in thermodynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conversion of calories to joules and question the appropriate equations for calculating the heat required to melt ice. There is a focus on understanding the difference between sensible heat and latent heat.

Discussion Status

The discussion is ongoing, with participants expressing confusion about the concepts and seeking clarification on the relevant equations. Some guidance has been provided regarding the need to consider latent heat, but no consensus or clear direction has been reached yet.

Contextual Notes

Participants mention a time constraint due to an upcoming test, which adds pressure to understand the material quickly. There is also a noted lack of familiarity with the necessary conversions and equations involved in the problem.

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Homework Statement



The exact question is "how many kg of ice can you melt, assuming it is at the melting point, with 178,000 cal of heat"

Homework Equations





The Attempt at a Solution


I can't give any other imformation. I have know idea where to even, start with solving this problem. I really need help! Big test tomorrow...
 
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Well how much Joules is 178,000 calories? What formula will show you the energy required to melt 'm' kilograms of ice? (Hint: what equation do you use for heat required to change the phase of a substance? Not sensible heat but?)
 
The equation for heat I believe is Q = mcΔT or Q=cpmΔT
I am still totally lost. I have no ideas how many joules are in 178,000 calories all this looks pretty foreign to me. I need help breaking this down, to have any chance of passing this test tomorrow.
 
cwalker8184 said:
The equation for heat I believe is Q = mcΔT or Q=cpmΔT

Right, that's the equation if I want to find how much heat I need to raise the temperature of something. That's called sensible heat.


cwalker8184 said:
I am still totally lost. I have no ideas how many joules are in 178,000 calories all this looks pretty foreign to me. I need help breaking this down, to have any chance of passing this test tomorrow.

Have you ever heard of latent heat?
 

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