I in finding correct Coefficient of friction

AI Thread Summary
To bring a vehicle traveling at 100 km/h to a stop with a deceleration of 3.2 m/s², the coefficient of friction between the wheels and the road must be at least 1. The force exerted during braking is equal to the vehicle's mass multiplied by the deceleration. Some participants noted that the standard acceleration due to gravity is approximately 9.7 m/s², which differs from the 3.2 m/s² used in the initial calculations. Accurate calculations require understanding the relationship between friction force and the coefficient of friction. The discussion emphasizes the importance of showing calculations for assistance in solving such problems.
akki2063
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A road vehicle equipped with mechanical wheel brake e.g drum or disc brake ,driving at a speed of 100Km/hr is braked to a stand still with a deceleration of 1G (3.2m/sec^2),How large must be the coefficient if friction between wheel and road at least be to enable that.

Options:

1)At least 1.
2)0.5
3)2
 
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The force exerted on the truck when the brakes come on ( and lock the wheels) is mg, g=3.2ms-2 and m is the trucks mass.

Can you calculate the force provided by the friction in terms of the coefficient of friction ?

(Incidentally the acceleration on the Earth's surface is about 9.7ms-2, not 3.2)
 
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akki2063 said:
A road vehicle equipped with mechanical wheel brake e.g drum or disc brake ,driving at a speed of 100Km/hr is braked to a stand still with a deceleration of 1G (3.2m/sec^2),How large must be the coefficient if friction between wheel and road at least be to enable that.

Options:

1)At least 1.
2)0.5
3)2

Check your PMs. You *must* show your efforts before we can provide tutorial help. That is in the PF Rules (see the top of the page under Site Info).
 
Mentz114 said:
The force exerted on the truck when the brakes come on ( and lock the wheels) is mg, g=3.2ms-2 and m is the trucks mass.

Can you calculate the force provided by the friction in terms of the coefficient of friction ?

(Incidentally the acceleration on the Earth's surface is about 9.7ms-2, not 3.2)

I don't know where you got g = 9.7 m/s^2, but there is a different and more precise figure defined:

http://en.wikipedia.org/wiki/Standard_gravity
 
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