(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known dataA ball is dropped from rest from the top of a cliff that is 24 m high. From ground level, a second ball is thrown straight upward at the same instant that the 1st ball is dropped. The initial speed of the second ball is exactly the same as that which the 1st ball eventually hits the ground. In the absence of air resistance, the motions of the balls are just reverse of each other. Determine how far below the top of the cliff the balls cross paths.

Height= 24 m

2. Relevant equations

y=1/2 (Vo + V) t

y= Vot + 1/2at

V^2= Vo^2 + 2ay or y=V^2 - Vo^2/2a

3. The attempt at a solution

What equation should I use.

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# Homework Help: I must find distance.

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