I in finding correct Coefficient of friction

In summary: The centripetal force acting on the truck is F = m * a, where m is the mass of the truck, and a is the deceleration. Since the question asks for the coefficient of friction, we can set up the equation as:F = μ * NWhere μ is the coefficient of friction and N is the normal force (perpendicular to the surface). We can rearrange the equation to solve for μ:μ = F / NNow, the normal force can be calculated by taking the weight of the truck and multiplying it by the cosine of the angle between the truck and the road. In this case, the angle is 90 degrees since the truck is standing still. So the normal force is simply the
  • #1
akki2063
2
0
A road vehicle equipped with mechanical wheel brake e.g drum or disc brake ,driving at a speed of 100Km/hr is braked to a stand still with a deceleration of 1G (3.2m/sec^2),How large must be the coefficient if friction between wheel and road at least be to enable that.

Options:

1)At least 1.
2)0.5
3)2
 
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  • #2
The force exerted on the truck when the brakes come on ( and lock the wheels) is mg, g=3.2ms-2 and m is the trucks mass.

Can you calculate the force provided by the friction in terms of the coefficient of friction ?

(Incidentally the acceleration on the Earth's surface is about 9.7ms-2, not 3.2)
 
Last edited:
  • #3
akki2063 said:
A road vehicle equipped with mechanical wheel brake e.g drum or disc brake ,driving at a speed of 100Km/hr is braked to a stand still with a deceleration of 1G (3.2m/sec^2),How large must be the coefficient if friction between wheel and road at least be to enable that.

Options:

1)At least 1.
2)0.5
3)2

Check your PMs. You *must* show your efforts before we can provide tutorial help. That is in the PF Rules (see the top of the page under Site Info).
 
  • #4
Mentz114 said:
The force exerted on the truck when the brakes come on ( and lock the wheels) is mg, g=3.2ms-2 and m is the trucks mass.

Can you calculate the force provided by the friction in terms of the coefficient of friction ?

(Incidentally the acceleration on the Earth's surface is about 9.7ms-2, not 3.2)

I don't know where you got g = 9.7 m/s^2, but there is a different and more precise figure defined:

http://en.wikipedia.org/wiki/Standard_gravity
 
  • #5


Based on the given information, the coefficient of friction between the wheel and the road must be at least 0.5 to enable the vehicle to come to a complete stop with a deceleration of 1G. This value may vary depending on the specific design and conditions of the vehicle's braking system, but a minimum of 0.5 is necessary to achieve the desired result. It is important to note that other factors such as tire tread and road surface can also affect the coefficient of friction and should be taken into consideration when determining the appropriate value for a specific vehicle.
 

1. What is the coefficient of friction?

The coefficient of friction is a measure of the amount of resistance between two surfaces in contact with each other. It is a dimensionless value that represents the ratio of the force required to move one surface over the other to the force pressing the two surfaces together.

2. How is the coefficient of friction calculated?

The coefficient of friction is calculated by dividing the force required to move one surface over the other by the force pressing the two surfaces together. This can be done using a variety of methods, including using an inclined plane or a friction testing machine.

3. What factors affect the coefficient of friction?

The coefficient of friction can be affected by a variety of factors, including the type of material of the two surfaces in contact, the roughness of the surfaces, the amount of force pressing the surfaces together, and the presence of any lubricants or contaminants on the surfaces.

4. Why is it important to find the correct coefficient of friction?

It is important to find the correct coefficient of friction in order to accurately predict and understand the behavior of objects in contact with each other. This information is crucial in various industries such as engineering, manufacturing, and transportation.

5. How can the coefficient of friction be used in real-world applications?

The coefficient of friction has many practical applications, such as helping engineers design and improve machines and structures, determining the maximum load that a surface can support, and predicting the movement of objects on different surfaces. It is also used in safety measures, such as designing appropriate footwear for different types of surfaces to prevent slips and falls.

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