Good. So how can you apply this to solve for the time it takes for the 20 m/s object to reach the ground?Purpplehaze said:D= iV * T + a*t^2/2 I think that's the formula to be used.
Purpplehaze said:D= iV * T + a*t^2/2 I think that's the formula to be used.
Purpplehaze said:Would this work? 2(D-iV)/a = t
No.Purpplehaze said:Would this work? 2(D-iV)/a = t
Purpplehaze said:Then how can I isolate t?
Purpplehaze said:60=20t + 4.9t^2
Good. Now you can put it into standard form and solve it using the quadratic formula (or using whatever method you like).Purpplehaze said:60=20t + 4.9t^2
Good!Purpplehaze said:I got 2 as T for the first one.
Freefall is the motion of an object falling under the sole influence of gravity. In this type of motion, the object is accelerating towards the ground at a constant rate of 9.8 meters per second squared.
The distance of a freefalling object can be calculated using the equation d = 1/2 x g x t^2, where d is the distance, g is the acceleration due to gravity, and t is the time in seconds.
Objects fall at the same rate in freefall because the acceleration due to gravity is constant and does not depend on the mass or size of the object. This means that all objects, regardless of their mass, will accelerate towards the ground at the same rate.
Air resistance can affect freefall by slowing down the acceleration of an object. As the object falls, it will encounter air molecules that will create a force in the opposite direction of its motion, known as drag. This force will increase as the object's velocity increases, eventually reaching a point where it is equal to the force of gravity, resulting in a constant velocity known as terminal velocity.
Yes, an object's shape can affect its freefall distance. Objects with larger surface areas will experience more air resistance, which can slow down their acceleration and decrease their freefall distance. On the other hand, objects with smaller surface areas will have less air resistance and may have a longer freefall distance.