Understanding Relativity: A Beginner's Guide to Tensors

In summary: What do you mean by more careful or rather why do you have to be careful?You might want to be careful because there are different ways to define a covector, and sometimes they can look very different. So it can be difficult to tell at a glance what's a covector and what's not.
  • #1
Storm Butler
78
0

Homework Statement


I just started trying to get into relativity using Schutz's book but I've been getting a little confused with some of the tensor stuff. For starters, what does it mean by a one form maps covectors to real numbers? is it an operation or a transformation? and when it maps to a real number does that mean it will loose information about its direction? Also i don't understand some of the notation for example i get that A with a superscript alpha is the alpha component of the vector but then why are the basis vectors written with a subscript ( is this the whole contrivariant covariant part) also two subscripts(alpha beta) next to one another, i understand is just a matrix at the alpha row beta column. But i don't get it when there is a something with an alpha beta component one on top and one on the bottom (and they arent even in a vertical line one is shifted from the other. i tried looking up some of these question in penroses the road to reality book but i got confused at the part where he give a coordinate change where X= x , Y= y+x but then the partial with respect to X= the partial with respect to x minus the partial with respect to y while the partial of Y= the partial with respect to y (on page 189). sorry for the lack of math symbols i don't really know how to add them in.
-thanks for all the help anyone can offer.


this isn't HW just something I am doing on my own but i figured it was the most appropriate place to put the question.
 
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  • #2
Hi Storm Butler! :smile:

(have an alpha: α and a beta: β and for indices, use the X2 and X2 tags just above the Reply box :wink:)
Storm Butler said:
For starters, what does it mean by a one form maps covectors to real numbers? is it an operation or a transformation? and when it maps to a real number does that mean it will loose information about its direction?

I don't see any difference between an operation and a transformation … a one-form is simply a function from one space to another.

And yes, it loses information about direction. :smile:
Also i don't understand some of the notation for example i get that A with a superscript alpha is the alpha component of the vector but then why are the basis vectors written with a subscript ( is this the whole contrivariant covariant part) …

Components and vectors are completely different animals, and live in different spaces.

One lives upstairs, the other lives downstairs. :wink:
… also two subscripts(alpha beta) next to one another, i understand is just a matrix at the alpha row beta column. But i don't get it when there is a something with an alpha beta component one on top and one on the bottom (and they arent even in a vertical line one is shifted from the other.

It's still a matrix entry … you just have to be more careful than usual about how you use it. :smile:
 
  • #3
but what do you mean when you say that they are different components? does the notion of a vectors components being the projection of the vector onto the basis still apply or is their a new definition? and if there is a matrix Mab and another matrix Mab what is the difference? and if a one form is not a vector then how is there a concept of components? What do you mean by more careful or rather why do you have to be careful?
 
  • #4
Storm Butler said:
For starters, what does it mean by a one form maps covectors to real numbers? is it an operation or a transformation?
If V is a vector space over [itex]\mathbb R[/itex], its dual space V* is the set of linear functions from V into [itex]\mathbb R[/itex]. The definitions

(x*+y*)(z)=x*z+y*z for all z in V
(ax*)z=a(x*z) for all z in V, all [itex]a\in\mathbb R[/itex]

give V* the structure of a vector space. So dual vectors are vectors too, because they're members of a vector space. I prefer not to call them "covectors" until we have defined V to be the tangent space at a point p of a manifold M. Then the members of V are called tangent vectors at p and the members of V* are called cotangent vectors at p, or covectors at p.

I don't know what you mean when you ask "is it an operation or a transformation?". Aren't those terms synonymous to you? The word "operator" is sometimes reserved for linear functions from a vector space into the same vector space, so you might want to avoid that term. "Operation" is not a term I use. Linear functions from a vector space over a field F into F are often called "functionals", so you can use that one if you want.

Storm Butler said:
and when it maps to a real number does that mean it will loose information about its direction?
Yes.

Storm Butler said:
Also i don't understand some of the notation for example i get that A with a superscript alpha is the alpha component of the vector but then why are the basis vectors written with a subscript
It's just a notational convention. It's a convenient way to see what type of tensor you're working with just by looking at the notation for its components.

Storm Butler said:
also two subscripts(alpha beta) next to one another, i understand is just a matrix at the alpha row beta column.
Not really. It's a component of a tensor of type (0,2). That's a bilinear function from V×V into [itex]\mathbb R[/itex].

(Note that what some authors call a tensor of type (i,j), others call a tensor of type (j,i). I don't remember what Schutz calls it).

Storm Butler said:
But i don't get it when there is a something with an alpha beta component one on top and one on the bottom (and they arent even in a vertical line one is shifted from the other.
For example, [itex]M_{ij}{}^k[/itex] means

[tex]M(\vec e_i,\vec e_j,\tilde e^k)[/tex]

where [tex]\tilde e^k[/tex] is the kth member of the dual basis to [tex]\{\vec e_i\}[/tex]. The dual basis of a basis for V is a basis for V* defined by

[tex]\tilde e^i(\vec e_j)=\delta^i_j[/tex]

So the positions of the indices on a component of this particular M let's you know that it's a multilinear function

[tex]M:V\times V\times V^*\rightarrow\mathbb R[/tex]
In my opinion, questions like this belong in the topology & geometry section, but they usually get posted in the relativity section.
 
  • #5
to start off i think i should clear up my operation or transformation statement i wasn't asking if it was one or the other i was just asking is it something of that nature i probably shouldn't have said both at once i see where the confusion came up. Also just out of curiosity in shutz's book (at least so far) the concepts of manifolds and dual vector spaces aren't really explicitly talked about (I'm only in the tensor analysis section) would you consider that a more geometric interpretation of a tensor? Also i know that you said that it is just a notational convention but i think that it is the notation that is really getting me stuck because i don't understand (for example) what the difference would be between Mij if it were written out explicltly as a matrix (like with columns and rows written out with the elements) from Mij. I just don't understand the difference. Or, there is another part where he shows a basis vector as {e0}B but how does that make sense? a basis vector is a vector so it can't have multiple elements. (Also can anyone answer the question i had earlier on whether or not the concept of components being a projection onto the basis vectors still applies?)

Are you saying that you think i should move my question to a different section?
 
  • #6
Storm Butler said:
Also just out of curiosity in shutz's book (at least so far) the concepts of manifolds and dual vector spaces aren't really explicitly talked about (I'm only in the tensor analysis section) would you consider that a more geometric interpretation of a tensor?
Not really. A tensor is a multilinear map from a cartesian product involving a finite number of factors of V and V* into the real numbers. For example

[tex]T:V\times V^*\times V\times V\rightarrow\mathbb R[/tex].

A manifold M has a vector space TpM associated with each point p in M. So the choice V=TpM isn't "a more geometric interpretation of a tensor". It's just a special case.

Storm Butler said:
Also i know that you said that it is just a notational convention but i think that it is the notation that is really getting me stuck because i don't understand (for example) what the difference would be between Mij if it were written out explicltly as a matrix (like with columns and rows written out with the elements) from Mij. I just don't understand the difference.
They're just the components of two different tensors, regardless of whether you put them into a matrix or not.

Another convention is to use the metric to "raise and lower indices". For example, if T is a tensor of type (0,2), you can use T and the metric to define two different tensors of type (1,1) by saying that the first new tensor has components [itex]T^i{}_j=g^{ij}T_{jk}[/tex], and the second one has components [itex]T_i{}^j=T_{ik}g^{kj}[/itex]. You can't call the new tensors "T" when you're using the the index-free notation, but their components would be written as a "T" with a bunch of indices, as I just did.

Storm Butler said:
Or, there is another part where he shows a basis vector as {e0}B but how does that make sense? a basis vector is a vector so it can't have multiple elements.
What if you write a basis vector as a linear combination of the members of another basis? Wouldn't a notation like that be appropriate then? For example

[tex]\vec e_i=(\vec e_i)^j \vec f_j[/tex]

Storm Butler said:
(Also can anyone answer the question i had earlier on whether or not the concept of components being a projection onto the basis vectors still applies?)
If an inner product is defined, then yes. We are just talking about vector spaces here, so everything you learned in your linear algebra class still applies. The first thing that's going to be different is that you're going to be using a bilinear form that isn't positive definite (a Lorentzian metric tensor) instead of an inner product.

Storm Butler said:
Are you saying that you think i should move my question to a different section?
It doesn't matter to me. I was just answering the comment you made about "the most appropriate place to put the question". If you want to move it, you can hit the report button and request a move.
 

1. What is relativity and why is it important?

Relativity is a theory in physics that explains how objects move and interact with each other in the universe. It is important because it has revolutionized our understanding of space, time, and gravity, and has been confirmed by countless experiments and observations.

2. What are tensors and how do they relate to relativity?

Tensors are mathematical objects that describe the relationships between different physical quantities, such as position, velocity, and acceleration. In relativity, tensors are used to describe the curvature of spacetime and how it is affected by mass and energy.

3. Is it possible for a beginner to understand relativity?

Yes, it is possible for a beginner to understand the basics of relativity. However, it may require some effort and patience to fully grasp the concepts and mathematical equations involved. This book, "Understanding Relativity: A Beginner's Guide to Tensors", aims to make the subject more accessible and comprehensible for beginners.

4. How does relativity impact our daily lives?

Relativity has many practical applications that affect our daily lives. For example, the Global Positioning System (GPS) would not function accurately without taking into account the effects of relativity on time dilation. Relativity also plays a crucial role in modern technologies such as particle accelerators and nuclear power plants.

5. Are there any real-life examples that can help illustrate the concept of relativity?

One famous example of relativity is the Twin Paradox, where one twin travels in a high-speed spaceship while the other stays on Earth. When the traveling twin returns, they will have aged less than the twin on Earth due to the effects of time dilation. Another example is the bending of light around massive objects, such as stars, which was famously observed during a solar eclipse in 1919 and confirmed Einstein's theory of general relativity.

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