Why is the first ionization energy for sodium smaller than the second?

  • Thread starter Thread starter Pechy
  • Start date Start date
  • Tags Tags
    Homework
AI Thread Summary
The first ionization energy of sodium is smaller than the second due to the differences in electron shell configuration and atomic charge. When the first electron is removed, sodium becomes a positively charged ion, which increases the effective nuclear charge experienced by the remaining electrons. This makes the second electron significantly harder to remove. The discussion emphasizes that this principle applies not only to sodium but to other elements as well. Understanding these concepts is crucial for grasping ionization energy trends in the periodic table.
Pechy
Messages
1
Reaction score
0
WHy is the first ionization energy for sodium much smaller than the secon ionization energy for sodium? i don't understand this.
 
Physics news on Phys.org
Hi there Pechy and welcome to PF,

Why do you think it is? Think about shell configuration and atomic charge.
 
Shell configuration ??
Atomic charge total is zero ... the ionized sodium is a positive ION.

THAT is the main reason the second electron is much harder to remove ...
for ANY object, not just a sodium atom/ion.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top