I need to know if i correct (Chemistry)

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The empirical formula CH2 corresponds to a molecular formula of C4H8 when the molar mass is 56 g/mol. The oxidation number of manganese in KMnO4 is +7, while potassium has an oxidation number of +1 and oxygen has -2. The discussion clarified that oxidation numbers pertain to individual atoms rather than the entire molecule. The initial confusion about the wording was acknowledged, but the correct interpretation was confirmed. Overall, the molecular formula is C4H8, and manganese in KMnO4 has an oxidation state of +7.
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if is known that for some Compound have Empirical formula CH2 and molar mass of 56 g/mol

so the Molecular formula of this Compound will be C4H8 ?


and other Question that i need to know if i correct is: the Oxidation number of KMnO4 is +7 ?

thanks.
 
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omni said:
so the Molecular formula of this Compound will be C4H8 ?

Yes.

is: the Oxidation number of KMnO4 is +7 ?

Oxidation number is a property of atom, not a molecule. But I guess it is just a lousy wording and you are on the right track.
 
hi. thank you for yours answer
about KMnO4 i got 4 Different Options and this was my Options :

A)+7
B)+2
C)+3
D)+4
so found is A what do you say?
and thanks again.
 
You still don't understand. There is no such thing as oxidation number of KMnO4. But K in KMnO4 has oxidation number of +1. O in KMnO4 has oxidation number of -2. And so on.
 
The question probably asked for the oxidation number for manganese in the compound KMnO4.
 
yes yes exactly as chemisttree told is asked about manganese in the compound KMnO4 so the answer still the same?

and sorry about the Bad wording.
thanks.
 
omni said:
yes yes exactly as chemisttree told is asked about manganese in the compound

I hoped you will get in on your own.

+7 it is.
 

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