Ideal gas: Temperture at 1 atm

AI Thread Summary
The total internal energy of an ideal gas is given as 3770 J for 3 moles at 1 atm. The formula U=3/2*n*R*T is used to calculate temperature, but the initial calculation yields 101 K, which seems incorrect. Participants question whether the internal energy is stated as 3770 J or 3770 J/mole, which could affect the temperature calculation. The discussion highlights the implausibility of the gas being at such a low temperature under the given conditions. Clarification on the energy unit is crucial for accurate temperature determination.
Baronen
Messages
2
Reaction score
0
Summary: U=3/2*n*R*T

Can some of you help me with this

The total internal energy of an ideal gas is 3770 J. If there are 3 moles of the gas at 1 atm, what is the temperature of the gas?

I use U=3/2*n*R*T but get the wrong answer, (101 K) but it should be 303 K

[Moderator's note: Moved from a technical forum and thus no template.]
 
Last edited by a moderator:
Physics news on Phys.org
Baronen said:
Summary: U=3/2*n*R*T

Can some of you help me with this

The total internal energy of an ideal gas is 3770 J. If there are 3 moles of the gas at 1 atm, what is the temperature of the gas?

I use U=3/2*n*R*T but get the wrong answer, (101 K) but it should be 303 K

[Moderator's note: Moved from a technical forum and thus no template.]
Hi Baronen
The only thing I can think of is with this line.
The total internal energy of an ideal gas is 3770 J

Does it say 3770J,
or
3770 J/mole
Otherwise I get the same answer as you.
 
Hey 256Bits

Thanks for the reply.

The question is formed as stated above.
But if you look at it, would a idealgas be 101 K at 1 atm if you have 3 moles of it (that is very cold).

Baronen
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Calculating ΔE Difference for 2 Samples of Monatomic Ideal Gas
Replies
4
Views
2K
Internal Energy of an Ideal Gas
Replies
4
Views
2K
Closed cycle of an ideal gas
Replies
3
Views
1K
Thermodynamics: gas expansion formula or approximation error?
Replies
2
Views
1K
Ideal Gas Law and Pressure at 80°C
Replies
2
Views
3K
Calculating Work Done by Gas at Constant Pressure
Replies
2
Views
2K
Calculate Temperature of Nitrogen Gas at 2 atm Pressure
Replies
7
Views
1K
Calculations using the Ideal Gas Law
Replies
2
Views
2K
Find temperature of a U-shaped Tube
Replies
9
Views
768
Calculating Hydrogen Mass from Ideal Gas Law
Replies
3
Views
4K

Hot Threads

Recent Insights

Back
Top