Ideal Mechanical Advantage of a Lever with 65N Force and 60/10 cm Arms

AI Thread Summary
The Ideal Mechanical Advantage (IMA) of a lever is calculated by dividing the length of the effort arm by the length of the resistance arm. In this case, with an effort arm of 60 cm and a resistance arm of 10 cm, the IMA is 6. The 65 N force is the amount of effort applied to lift the box but does not affect the IMA calculation directly. The discussion emphasizes understanding the relationship between arm lengths and the mechanical advantage, while the force value serves to illustrate the effort used. The key takeaway is that the IMA is 6, demonstrating the lever's efficiency in lifting the load.
billnyerocks
Messages
5
Reaction score
0
A man uses 65 N to lift a box off the ground with a lever. The effort arm is 60 cm. The resistance arm is 10 cm. What is the Ideal Mechanical Advantage?
 
Physics news on Phys.org
You need to show us an attempt to solve the problem yourself. What have you tried?
 
I know that the IMA of a lever is Le divided by Lr, which is Lever effort divided by lever resistance, so when you divide 60 cm by 10 cm, you get 6 cm. But what is the 65 N for?
 
billnyerocks said:
I know that the IMA of a lever is Le divided by Lr, which is Lever effort divided by lever resistance, so when you divide 60 cm by 10 cm, you get 6 cm. But what is the 65 N for?

Please do not double post your questions.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top