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Ideal Projectile Motion , horizontal and vertical components

  1. Oct 21, 2009 #1
    1. The problem statement, all variables and given/known data

    You throw a ball toward a wall with a speed of 32 m/s at an angle of 40.0° above the horizontal directly toward a wall (Fig. 5-33). The wall is 22.0 m from the release point of the ball.


    (a) How far above the release point does the ball hit the wall?
    not sure what to do

    (b) What are the horizontal and vertical components of its velocity as it hits the wall?

    Vx = 32m/s * cos 40
    Vx 24.513 i know this is correct
    Vy = 32m/s * Sin 40
    Vy= 20.569 this isnt correct i dont know what i did wrong
     
  2. jcsd
  3. Oct 21, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    Distance of the wall is given. The time taken by ball to reach the wall is
    t = d/vx.
    Using
    y = vy*t - 1/2*g*t^2, find y, and vy at that point
     
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