Ideal Projectile Motion , horizontal and vertical components

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SUMMARY

The discussion focuses on solving a projectile motion problem involving a ball thrown at a speed of 32 m/s at an angle of 40.0° towards a wall located 22.0 m away. The horizontal component of the velocity, calculated as Vx = 32 m/s * cos(40°), is confirmed to be 24.513 m/s. The vertical component of the velocity, initially calculated as Vy = 32 m/s * sin(40°), was found to be incorrect, prompting a reevaluation of the calculations for vertical motion using the time of flight and gravitational effects.

PREREQUISITES
  • Understanding of projectile motion principles
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with kinematic equations
  • Basic concepts of gravity and its effect on motion
NEXT STEPS
  • Review the derivation of projectile motion equations
  • Learn how to calculate time of flight in projectile motion
  • Study the effects of gravity on vertical motion
  • Practice solving similar projectile motion problems with varying angles and speeds
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Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for examples of real-world applications of kinematic equations.

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Homework Statement



You throw a ball toward a wall with a speed of 32 m/s at an angle of 40.0° above the horizontal directly toward a wall (Fig. 5-33). The wall is 22.0 m from the release point of the ball.


(a) How far above the release point does the ball hit the wall?
not sure what to do

(b) What are the horizontal and vertical components of its velocity as it hits the wall?

Vx = 32m/s * cos 40
Vx 24.513 i know this is correct
Vy = 32m/s * Sin 40
Vy= 20.569 this isn't correct i don't know what i did wrong
 
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Distance of the wall is given. The time taken by ball to reach the wall is
t = d/vx.
Using
y = vy*t - 1/2*g*t^2, find y, and vy at that point
 

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