Yes.eehelp150 said:Are these correct?
Turn ratio: N=V2/V1 = 0.418
kVA = S1*I1 = S2*I2 = 4600*30 = 138kVA
Primary current: V1*I2 = V2*I2=>I1=(4600*30)/(11000) = 12.5A
The turn ratio for an ideal transformer can be calculated by dividing the number of turns in the secondary coil by the number of turns in the primary coil. This is also known as the voltage ratio, as it determines the relationship between the input and output voltages of the transformer.
To solve for the kVA rating of an ideal transformer, you can use the formula kVA = (Vp x Ip)/1000, where Vp is the primary voltage and Ip is the primary current. This will give you the apparent power rating of the transformer in kilovolt-amperes (kVA).
The turn ratio in an ideal transformer is important because it determines the voltage ratio and current ratio between the primary and secondary coils. It also affects the power transfer efficiency and determines the impedance transformation ratio of the transformer.
The primary current of an ideal transformer can be calculated by dividing the secondary current by the turn ratio. This means that the primary current will be lower than the secondary current, depending on the turn ratio of the transformer.
If you know the secondary current and turn ratio of an ideal transformer, you can solve for the primary current by multiplying the secondary current by the reciprocal of the turn ratio. This will give you the primary current, which will be lower than the secondary current.