Identify the Gas at STP: 2.75 L & 5.39 g

[Oblivion77]

Homework Statement

At STP, 2.75 L of a gas weighed 5.39 g. The gas could be

a) N2
b) N2O
c) NO
d) F2
e) NF3

Homework Equations

I was thinking PV=nRT but it might not be.

The Attempt at a Solution

Nothing really.

Thanks!

 

[Borek]

I was thinking PV=nRT but it might not be.

That's the right one, although not sufficient one.

Nothing really

Get back once you try.

 

[Oblivion77]

That's the right one, although not sufficient one.



Get back once you try.

Do I need to use the fact that 1mol = 22.4L at STP?

 

[Borek]

Do I need to use the fact that 1mol = 22.4L at STP?

You may, although that's equivalent of using PV=nRT and entering standard TP (whatever that means).