Identifying Net Ionic Equations for Reactions

AI Thread Summary
The discussion focuses on identifying reactions and writing net ionic equations for various metal and solution interactions. Chromium reacts with silver nitrate, producing a net ionic equation involving chromium and silver ions. Gold does not react with hydrochloric acid, while nickel pellets show no reaction with calcium acetate. Aluminum reacts with sulfuric acid, leading to a net ionic equation that includes aluminum and hydrogen ions. Zinc reacts with lead(II) nitrate, resulting in a net ionic equation that features zinc and lead ions.
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Homework Statement



For each of the following situations, identify those for which a reaction is liely to occur. For those that do occur, write a net ionic equation

a) Chromium dipped into silver nitrate.
b) B) Gold immersed in hydrochloric acid.
c) Nickel pellets dropped into calcium acetate, Ca(C2H3O2)2.
d) Aluminum dropped into a bath of sulphuric acid.
e) Zinc dipped into a solution of lead (II) nitrate.


Homework Equations


solubility charts


The Attempt at a Solution


I can't really figure out how to form a net ionic equation or how to get the charge but here is my attempt so far
a) Cr(s) + 2 AgNO3(aq) -> Cr(NO3)2(aq) + 2 Ag(s)
b) Au(s) + HCl(aq) -> no reaction
c) Ni(s) + Ca(C2H3O2)2(aq) -> no reaction
d) 2 Al(s) + 3H2SO4(aq) -> Al2(SO4)3 + 3 H2
e) Zn(s) + Pb(NO3)2(aq) -> Zn(NO3)2(aq) + Pb(s)

if anyone can look over this i'd really appreciate it
 
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i attempted to form the net ionic equations I'm just still not sure if this is correct.

a) Chromium dipped into silver nitrate.
Cr(s) + 2 AgNO3(aq) -> Cr(NO3)2 (aq) + 2 Ag(s)
Therefore the net ionic equation is
Cr(s)+2 + Ag(aq)+ -> Cr(aq)+2 + Ag(s)+
b) Gold immersed in hydrochloric acid.
Au(s) + HCl(aq)-> no reaction
c) Nickel pellets dropped into calcium acetate, Ca(C2H3O2)2.
Ni(s) + Ca(C2H3O2)2 -> no reaction
d) Aluminum dropped into a bath of sulphuric acid.
2 Al(s) + 3 H2SO4(aq) -> Al2(SO4)3 + 3 H2
Therefore the net ionic equation is
2Al(s)+3 + H2(aq)+ -> Al2(aq)+3 + H2(g)+
e) Zinc dipped into a solution of lead (II) nitrate.
Zn(s) + Pb(NO3)2(aq) -> Zn(NO3)2(aq) + Pb(s)
Therefore the net ionic equation is
Zn(s)+2 + Pb(aq)+2 -> Zn(aq)+2 + Pb(s)+2
 
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