Identifying the Odd Resistor: How Many Measurements Are Needed with an Ohmmeter?

AI Thread Summary
To identify the odd resistor among nine with a value of 1 ohm, a strategic approach is necessary rather than measuring each resistor individually. The discussion suggests that measuring resistors in groups can optimize the process, potentially reducing the number of measurements needed. A method involving parallel and series configurations is proposed, which could lead to a maximum of five measurements depending on the arrangement and luck. The importance of not relying on chance is emphasized, as a systematic approach will yield the minimum number of measurements required. Ultimately, the focus is on finding an efficient strategy to solve the problem.
fshiznit
Messages
2
Reaction score
0
You receive a box of 9 resistors. All the resistors except one have a value of 1 ohm. With only an ohmmeter, what is the minimum number of measurements needed to identify the odd resistor and find its resistance.

-I've tried going up from one resistor, but I'm not sure what I'm doing past 4 resistors :S..any help is much appreciated!
 
Physics news on Phys.org
fshiznit said:
-I've tried going up from one resistor, but I'm not sure what I'm doing past 4 resistors :S..any help is much appreciated!
What do you mean by "going up from one resistor"? Please be more explicit in your explanation.
 
so for let's say 3 resistors, you'll need two measurements because say you take an even one and an odd one and get a resistance of 2.1 ohm (that's one measurement) then you take one off to which is the odd one and its resistance (second measurement). but now I am thinking, wouldn't the minimum measurements, even for the 9 resistor one, be just two measurements, seeing that you get lucky and pick the odd one when testing the first two resistors? But then i guess the question'd be too easy :S
 
As I interpret the question, assuming you are unlucky, what is the minimum number of measurements required?

A naive approach would be to measure them one-by-one and the odd one is the last resistor. However, you have to be a little clever here. Other than measuring one at a time, how else might you approach the problem?
 
would it make sense to put them in groups of 2 in parallel? (thus making 4 groups in series). Would that not only take a max. of 5 measurements depending on your luck?
 
Hint: measure resistances across multiple elements at once and think about what that tells you. You cannot rely on luck to get the minimum number of measurements.
 
FYI to everybody:

We really should let fshiznit try to solve the problem, and let him/her respond with questions, before giving further help.
 
Back
Top