If a and b are rational numbers satisfying

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SUMMARY

Proposition 1.15 asserts that for any two real numbers a and b where a < b, there exist both rational and irrational numbers between them. The Archimedean property is essential for proving this proposition. By demonstrating that the midpoint (a+b)/2 lies strictly between a and b, one can further explore the existence of rational and irrational numbers in that interval. A specific suggestion includes using a = 0 to simplify the proof process.

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Homework Statement



Prove Proposition 1.15.

Proposition 1.15. If a and b are real numbers satisfying a<b, then there are rational numbers and irrational numbers between a and b.

Homework Equations



Professor said to use the Archimedean property

The Attempt at a Solution



a < b ---> (a+a)/2 < (a+b)/2 ---> a < (a+b)/2

Similarly,

a < b ---> (a+b)/2 < (b+b)/2 ---> (a+b)/2 < b

Hence a < (a+b)/2 < b

Now I need some way to show that (a+b)/2 can equal rational and irrational numbers. Any suggestions?
 
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Hi Jamin2112! :smile:

But you haven't used the Archimedean property.

Hint: try it with a = 0. :wink:
 

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