aawahab76
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I completely agree as that is resulting from the postulate of special relativity. However, what do you think of the following picture:JesseM said:Because "absolute simultaneity" means a single truth about simultaneity that is the same for all observers. Two events that are simultaneous in F will not be simultaneous when their coordinates are translated into F', and vice versa.
1- O (I think it is obvious when O mean the event (0,0) or the observer in x=0, similarly for O' below) built F coordinates using rulers-clocks so whenever the clock at O reads 1 pm (or any other reading), all clocks at the whole space read 1 pm (or the other reading). This can be proved by using your (I think) proposed cameras when the pictures arrive.
2- As in 1, O' built F' so whenever the clock at O' reads 2' pm (or any other reading), all clocks at the whole space read 2' pm (or the other reading).
3- Notice the whole space is a physical entity that is independent of coordinate or frame being used. So usually we have F clock overlapping F' clock (of course the whole structure is imaginary).
4- When O meet O', their respective time coordinates read 0 and 0'. Each observer is certain at this moment that all other clocks (treating those for F independently of those of F') that are covering the whole space are reading the same, in this case 0 and 0'. This again can be proved using the cameras.
5- At the meeting of O and O', P (an explosion) is 1 sec in the future of F. So at the meeting, P is no where in the whole "space" but have already been there according to F'. That is because the reading of the clock at O' when P happened according to F' was -10^81 sec which is certainly before the meeting moment. I am picturing here that all F' clocks at the moment -10^81 sec in F' were reading -10^81 sec and it seems that at least one such clock was overlapping the location of O (the observer) whose clock was certainly before 0 (in F) because O (the event) is in the future.