If her mass is 50.0kg what is the tension on the rope?

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To calculate the tension in the rope when a person with a mass of 50.0 kg walks across it, the force of gravity acting on her is 490 N. The tension is the same on both sides of the rope since she is positioned at the center. A force diagram and trigonometric functions are necessary to resolve the forces acting along the rope. The calculation involves using the cosine of the sag angle (10 degrees) and the horizontal distance (5 m) to find the tension. The final conclusion is that the tension does not need to be multiplied by two, as it remains constant throughout the rope.
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Any Help would be appreciated

Problem 1:
A person is to walk across a high wire strung horiziontally between 2 buildings 10.0 m apart. The sag when she is in the exact center of the rope is 10*. If her mass is 50.0kg what is the tension on the rope?


Okay I know that the tension on the rope will be the same on each side as she is in the center of the rope. I also found the force of gravity to be 490N. but I am confused as too how I use this information to find the tension of the rope.
 
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You need to draw a force diagram and use trig to work out the component of the force acting along the length of the wire.
 
ok so I used cos10* X 5m and got 4.92N for the tension of one rope so then do i just times it by two and will then have the tension throughtout the entire rope?
 
I did not check you numbers to see if the tension is correct, but, the tension in the rope will be the same throughout. So to answer your question, no, you do not multiple your answer by two.
 
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