If her mass is 50.0kg what is the tension on the rope?

  • Thread starter Thread starter engineer2010
  • Start date Start date
  • Tags Tags
    Mass Rope Tension
AI Thread Summary
To calculate the tension in the rope when a person with a mass of 50.0 kg walks across it, the force of gravity acting on her is 490 N. The tension is the same on both sides of the rope since she is positioned at the center. A force diagram and trigonometric functions are necessary to resolve the forces acting along the rope. The calculation involves using the cosine of the sag angle (10 degrees) and the horizontal distance (5 m) to find the tension. The final conclusion is that the tension does not need to be multiplied by two, as it remains constant throughout the rope.
engineer2010
Messages
10
Reaction score
0
Any Help would be appreciated

Problem 1:
A person is to walk across a high wire strung horiziontally between 2 buildings 10.0 m apart. The sag when she is in the exact center of the rope is 10*. If her mass is 50.0kg what is the tension on the rope?


Okay I know that the tension on the rope will be the same on each side as she is in the center of the rope. I also found the force of gravity to be 490N. but I am confused as too how I use this information to find the tension of the rope.
 
Physics news on Phys.org
You need to draw a force diagram and use trig to work out the component of the force acting along the length of the wire.
 
ok so I used cos10* X 5m and got 4.92N for the tension of one rope so then do i just times it by two and will then have the tension throughtout the entire rope?
 
I did not check you numbers to see if the tension is correct, but, the tension in the rope will be the same throughout. So to answer your question, no, you do not multiple your answer by two.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Point mechanics -- Tension in a rope from a hanging mass
Replies
10
Views
2K
Dynamics of a Cord: Solving Tension for Arlene
Replies
3
Views
4K
Tension in two ropes attached to a beam
Replies
8
Views
10K
Tension in two ropes holding a board
Replies
2
Views
3K
Two masses connected by a weighted rope pulled vertically
Replies
5
Views
5K
Tension in the wire connecting two blocks
Replies
5
Views
2K
Calculating Tension in a Telephone Wire with Mass and Angle
Replies
5
Views
3K
How to find distance that the rope must sag
Replies
9
Views
4K
What is the tension and velocity in a rope attached to a moving space station?
Replies
3
Views
2K
What is the mass of this vertical rope? (Mechanical Waves)
Replies
10
Views
3K

Hot Threads

Recent Insights

Back
Top