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If someone says something about a fourth-order approximation, does that mean ?

  1. Jun 29, 2009 #1
    If someone says something about a "fourth-order approximation," does that mean...?

    ...that, say, if something is being approximated by a Taylor series expansion in which only the first few terms are retained, and the expansion is in a small parameter [itex]\kappa[/itex], we only keep the terms up to order [itex]\kappa^4[/itex]?
     
  2. jcsd
  3. Jun 29, 2009 #2
    Re: If someone says something about a "fourth-order approximation," does that mean...

    You got it.
     
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