If x goes very large, say infinite, what does this equation will look like

  • Thread starter Thread starter oxxiissiixxo
  • Start date Start date
  • Tags Tags
    Infinite
oxxiissiixxo
Messages
27
Reaction score
0
when x goes very large, say infinite, what does this equation will look like?

H is a constant

1) 1/(1+(x/H)^2)^(1/2))

2) 1/(1+(H/x)^2)^(1/2))

The answers are

1) 1/x^2

2) 1/x

But I am not too sure how to get there. Thank you
 
Physics news on Phys.org
1) 1 + x/h^2 is x/h^2 as x gets larger. Now you have 1 / (x/h^2)^1/2 which is h/x.

Try x = 10000 H = 5. => 4.99E-4. 5/10000 = 5E-4

2) (H/x)^2 is 1/x^2 as x gets larger? Then 1 + 1/x^2 is 1 as x gets larger. Now you have 1 / 1^1/2 which is 1.

Try x = 1000 H = 5. => .999.
 
Thread 'Use greedy vertex coloring algorithm to prove the upper bound of χ'
Hi! I am struggling with the exercise I mentioned under "Homework statement". The exercise is about a specific "greedy vertex coloring algorithm". One definition (which matches what my book uses) can be found here: https://people.cs.uchicago.edu/~laci/HANDOUTS/greedycoloring.pdf Here is also a screenshot of the relevant parts of the linked PDF, i.e. the def. of the algorithm: Sadly I don't have much to show as far as a solution attempt goes, as I am stuck on how to proceed. I thought...
Back
Top