If you find the scalar potential of a conservative vector field

AI Thread Summary
In the discussion about finding the scalar potential of a conservative vector field, participants debate whether to include the constant of integration in their answers. It is noted that technically, the constant should be included, but omitting it is acceptable as long as the relationship to the vector field is understood. The relevance of boundary conditions in determining a specific constant is also highlighted. The distinction between asking for "the" versus "a" scalar potential is emphasized, with the latter allowing for any valid potential. Ultimately, the uniqueness of scalar potentials for a given force field is acknowledged.
schattenjaeger
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Should your answer include the constant of integration? I think it should but my book's answers don't, so I dunno.

Example, <2xy^3, 3y^2x^2>

answer is x^2y^3, but should I include the + C? (and yes I went through and made sure h(y) was in fact a constant
 
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Technically, yes, you should include it.
Of course, a boundary condition might fix it to a specific constant.
From a (classical) physical point of view, it's the "difference in potential" that is physically relevant.
 
I would say yes. But it's OK to leave it out as long as you know that adding an arbitrary constant to the potential will produce the same vector field.
 
schattenjaeger said:
Should your answer include the constant of integration?

Did the question ask for "the" scalar potential? If so, then go to your teacher and toss a hot cup of coffee in his lap. Once you've got his attention, explain to him that scalar potentials for a given force field aren't unique.

Or did the question ask for "a" scalar potential? If so, then anyone will do.
 
Haha, hey, I like my teacher! It's actually outta the book, and it does say >A< scalar potential, had I been thinking it would've been clear, thanks though!
 
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