Image of Set S Under Transformation | u^2 + v^2 <= 1

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SUMMARY

The discussion focuses on finding the image of the set S, defined by the inequality u² + v² ≤ 1, under the transformation where x = au and y = bv. The boundaries of the transformed set are established as [-a, a] x [-b, b]. The transformation leads to the equations x = au, y = -b; x = a, y = bv; x = au, y = b; and x = -a, y = bv. The next step involves substituting u and v with x/a and y/b in the original inequality to determine the new boundary conditions.

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magnifik
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find the image of the set S under the given transformation: S is the disk given by u^2 + v^2 <= 1 where x=au, y=bv

since it is a circle i have that the boundaries are [-1,1] x [-1.1] so for my equations i got
x = au, y = -b
x = a, y = bv
x = au, y = b
x = -a, y = bv

i don't know what the next step would be in trying to draw that
 
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If x = au and y = bv, then u = x/a and v = y/b. I would replace u and v by x/a and y/b, respectively, in the given inequality.
 

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