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## Homework Statement

Imagine that a bullet is shot vertically into the air with an initial speed of 9800 m/s. If we ignore air friction, how high will it go?

v

_{i}= 9800 m/s

h = ?

## Homework Equations

v

^{2}= v

_{i}

^{2}+ 2aΔy

K

_{i}= U

_{i}--> 1/2mv

^{2}= mgh

F = (Gm

_{1}m

_{2})/r

## The Attempt at a Solution

__Attempt 1__

v

^{2}= v

_{i}

^{2}+ 2aΔy

0 = (9800 m/s)

^{2}+ 2(-9.8 m/s

^{2})(Δy)

Δy = 4,900,000 m

__Attempt 2__

1/2mv

^{2}= mgh

h = 4,900,000 m

Neither of these equations worked, so I tried using gravitational equations, but I couldn't figure it out.