Improper integral with substitution

ChristinaMaria
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Hi! I am trying to solve problems from previous exams to prepare for my own. In this problem I am supposed to find the improper integral by substituting one of the "elements", but I don't understand how to get from one given step to the next.

Homework Statement


Solve the integral
SrdRmDZ.png

by substituting u = sqrt(x)

Homework Equations


I don't understand how to get from step 1 to step 2:
HEnJgKc.png


The Attempt at a Solution


This is one of my attempts:
j6vAgRS.jpg

So, as I mentioned above I don't understand how to get from step one to two. I don't get what to do with the sqrt(x) you get in the expression dx = 2sqrt(x)du that I've written in the right corner. Where did it "go" in the step-by-step example? I can't seem to figure out how to remove it.

I hope this was easy enough to read.
Thanks :smile:
 

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You seem to have turned x+1 into u+1 at the start of the second line.
 
Last edited:
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Likes ChristinaMaria
ChristinaMaria said:
Hi! I am trying to solve problems from previous exams to prepare for my own. In this problem I am supposed to find the improper integral by substituting one of the "elements", but I don't understand how to get from one given step to the next.

Homework Statement


Solve the integral1
View attachment 235498
by substituting u = sqrt(x)

Homework Equations


I don't understand how to get from step 1 to step 2:
View attachment 235499

The Attempt at a Solution


This is one of my attempts:
View attachment 235500
So, as I mentioned above I don't understand how to get from step one to two. I don't get what to do with the sqrt(x) you get in the expression dx = 2sqrt(x)du that I've written in the right corner. Where did it "go" in the step-by-step example? I can't seem to figure out how to remove it.

I hope this was easy enough to read.
Thanks :smile:

From ##u = \sqrt{x}## we have
$$du = \frac 1 2 \frac{dx}{\sqrt{x}} \; \Rightarrow 2 du = \frac{dx}{\sqrt{x}}$$ and $$\frac{1}{x+1} =\frac{1}{u^2+1}.$$ Just put these together
 
  • Like
Likes ChristinaMaria
ChristinaMaria said:
I don't get what to do with the sqrt(x) you get in the expression dx = 2sqrt(x)du that I've written in the right corner. Where did it "go" in the step-by-step example? I can't seem to figure out how to remove it.
When you change the variable, do not keep the old one.
You have u=√x, This means x=u2. What is dx/du? what is dx then?
 
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