How Is Average Force Calculated in a Football Collision?

AI Thread Summary
The average force exerted on the post by the football is calculated using the formula F = m(vf - vi) / Δt, resulting in a force of -800 N. The mass of the football player is deemed irrelevant to this calculation, as his role is only to impart initial kinetic energy to the ball. The focus remains solely on the ball's mass and its change in velocity during the collision. The calculations confirm that the player's mass does not impact the average force exerted. Therefore, the solution is validated without considering the player's mass.
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Homework Statement



A football player whose mass is 85 kg throws a football with a mass of 0.8 kg against a post. The football hits the post traveling horizontally with a speed of 25 m/s, and then it bounces back with about the same speed. The football is in contact with the post for 0.05 s. What average force is exerted on the post by the ball?

m = 0.8 kg
vi = 25 m/s
vf = -25 m/s
t= 0.05s

Homework Equations



FΔt=m(vf-vi)

F = \frac{m(vf-vi)}{Δt}

The Attempt at a Solution



F = \frac{0.8(-25-25)}{.05-0} = -800N by the post.

Is the mass of the football player irrelevant?
 
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Why would the mass of the football player be relevant? All he does is imparts the initial kinetic energy to the ball. The same thing could be done with a 3,000kg piece of equipment. So yes, the football player's mass is irrelevant.
 
So my calculations are correct without the football player's mass?
 
Looks good to me.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

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