1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Impulse/Momentum Question

  1. Nov 7, 2008 #1

    There are two blocks one of mass m and the other of mass 3m. The blocks are both start at rest on a frictionless surface and are connected by a spring which is initially compressed. The blocks are then released. If the final kinetic energy of the block of mass 3m is E what is the final kinetic energy of the other block?

    My Understanding

    The one object that unites the two masses is the force of the spring. In this situation it would release it's energy equally in both directions at the same time. Given that I assumed that as the force is the same the 3m mass would travel at 1/3 the velocity but both objects would have the same overall kinetic energy that is 'E'.

    Now that answer turned out to be incorrect and it also confused me how a kinetic energy question appeared on an Impulse/Momentum quiz so I must be missing how kinetic energy and momentum directly relate to each other. I know that

    Momentum = mass x velocity
    Kinetic energy = (1/2)mv^2
    The force of the spring would cause the two masses to accelerate for a limited time, after which they would maintain a constant velocity with no acceleration.
    The spring would impart it's accelerating force on the two masses for an identical amount of time.

    The other possible answers were one such as E/3, E/9, 3E, 9 E, sqrt(E) etc.. so I assume it's related to the mv^2 equation but I don't see how.
  2. jcsd
  3. Nov 7, 2008 #2
    In the two boxes spring situation, it's not kinetic energy that is equally spread, but momentum. So the smaller mass must have 3x the velocity of the big one to equal out. Then, if K.E. = .5mv2 and momentum =mv then K.E. = .5v*momentum and solving for momentum gives momentum = (K.E.)/(.5v). If E is the kinetic energy of the big mass, and the big mass has velocity v, then the small mass has velocity 3v and the momenta are equal and can be set equal to each other.

    Momentum = Momentum
    (K.E.)/(.5v) = (K.E.)/(.5*3v)
    (E)/(.5v) = (?)/(.5*3v) [multiply both sides by .5v]
    E = (?)/3
    ? = 3*E
  4. Nov 7, 2008 #3
    Thank you for clearing that up.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Impulse/Momentum Question